15.03.2013 · AttributeError: 'datetime.date' object has no attribute 'date' 1415. UnicodeEncodeError: 'ascii' codec can't encode character u'\xa0' in position 20: ordinal not in range(128) 180. type object 'datetime.datetime' has no attribute 'datetime' 1203. Relative imports for the billionth time. 106.
... Hand integer IS1 Inventory Date datetime IS1 Reorder Level integer Table 6.20 ... It also has a corresponding Line Item attribute that together with the ...
Sort by. level 1. novel_yet_trivial. · 1y. To do what you want you need to convert to a string first. tom = datetime.date.today () + datetime.timedelta (days=1) print (str (tom).split ('/')) But you probably don't need to split the datetime value. What information are you trying to get out? To get the new day, for instance, use the day attribute:
25.09.2019 · This answer is not useful. Show activity on this post. If I understand your question correctly, then in your code: leave_remaining = self.end_day - datetime.timedelta (days=1) return leave_remaining.days. leave_remaining is a datetime.date that is 1 day prior to self.end_day, which I think is what you want; just return the date directly like ...
13.10.2018 · There are at least three problems with what you are trying to achieve: Don't use datetime.date objects within a Pandas series. Use Pandas-friendly pd.Timestamp to create datetime series via pd.to_datetime.This allows you to take advantage of NumPy arrays and efficient vectorised operations.
... today datetime.now(tz=None) Returns a datetime object for the current local date and time. When tz is not None, returns an aware datetime object with ...
15.10.2012 · from datetime import datetime. Then simply write the code as: date = datetime (int (year), int (month), 1) But if you have used: import datetime. then only you can write: date = datetime.datetime (int (2005), int (5), 1) Share. Improve this answer.