2. Applications of Differentiation
ocw.mit.edu › courses › mathematicsE. Solutions to 18.01 Exercises 2. Applications of Differentiation 2A-16 a) The law of cosines says that for a triangle with sides a, b, and c, with θ opposite the side of length c, c 2 = a 2 + b2 − 2ab cos θ Apply it to one of the n triangles with vertex at the origin: a = b = 1 and θ = 2π/n. So the formula is c = 2 − 2cos(2π/n)
Applications of Differentiation Handout
www.uis.edu › ctl › wp-contentApplications of Differentiation 3 The Closed Interval Method To find the absolute maximum and minimum values of a continuous function f on a closed interval[]a,b: 1. Find the values of f at the critical numbers of f in(a,b). 2. Find the values of f at the endpoints of the interval. 3.