25.06.2012 · 6. This answer is not useful. Show activity on this post. Your equations result in integers. You can't use in on integers. >>> 'foo' in 3 Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: argument of type 'int' is not iterable. Share. Improve this answer. Follow this answer to receive notifications.
In Python, the error TypeError: argument of type ‘int’ is not iterable occurs when the membership operator (in, not in) is used to validate the membership of a ...
19.08.2019 · argument of type 'int' is not iterable. Ask Question Asked 2 years, 4 months ago. Active 2 years, 4 months ago. Viewed 1k times 1 I am having a list with int values, iterating the same list with a loop, while iterating it I want to check the list, with some if condition, but am getting this issue: TypeError: argument of ...
21.12.2021 · Example #2: Invalid Sum Argument. The sum function returns an integer value and takes at most two arguments. The first argument must be an iterable object, and the second argument is optional and is the first number to start adding. If you do not use a second argument, the sum function will add to 0.
If choice is not 1 you cannot check "closer" in choice without potential errors, because choice can still be an integer (e.g. the number 2) and an integer is not iterable. It is best to keep the program simple and also to keep the return type from the input () function, i.e. the string. The string method is_digit () already exists and you can ...
In Python, the error TypeError: argument of type 'int' is not iterable occurs when the membership operator (in, not in) is used to validate the membership ...