This line raises an AttributeError: "Timestamp object has no attribute 'dt'": df['count'] = df.apply(last_day, axis=1) this is what my dataframe looks like: start count 0 2016-02-15 NaN 1 2016-02-20 NaN 2 2016-04-23 NaN df.dtypes start datetime64[ns] count float64 dtype: object
01.07.2015 · I'm guessing you should remove .dt in the second case. When you do apply it's applying to each element, .dt is needed when it's a group of data, if it's only one element you don't need .dt otherwise it will raise {AttributeError: 'Timestamp' object has no attribute 'dt'}
Oct 31, 2021 · Solution 1. The method to_datetime will return a TimeStamp instance. I’m not sure what you are hoping to accomplish by the lambda function, but it appears you are trying to convert some object to a TimeStamp. Try removing the apply section so it looks like this: Train ['timestamp'] = pd.to_datetime (Train ['date'])
timestamp = dt.replace (tzinfo=timezone.utc).timestamp () … or: timestamp = (dt - datetime (1970, 1, 1)) / timedelta (seconds=1) Since you don't have aware datetimes, that last one is all you need. If your Python is old enough, timedelta may not have a __div__ method. In that case (if you haven't found a backport), you have to do division ...
Jul 02, 2015 · I'm guessing you should remove .dt in the second case. When you do apply it's applying to each element, .dt is needed when it's a group of data, if it's only one element you don't need .dt otherwise it will raise {AttributeError: 'Timestamp' object has no attribute 'dt'}
01.01.2020 · Series has an accessor ( dt) object for datetime like properties. However, the following is a TimeDelta with no dt accessor: type (df.loc [0, 'timestamp'] - df.loc [1, 'timestamp']) Just call the following (without the dt accessor) to solve the error:
Nov 24, 2021 · Solution 2. The timestamp method was added in Python 3.3. So if you’re using Python 2.0, or even 2.7, you don’t have it. There are backports of current datetime to older Python versions on PyPI, but none of them seems to be official, or up-to-date; you might want to try searching for yourself. There are also a number of third-party ...
Jul 22, 2019 · python3 unix-timestamp.py. In case that is not possible e.g. due to incompatibilities, use this snippet instead, which is compatible with both Python 2 and Python 3: from datetime import datetime import time dt = datetime.now() timestamp = time.mktime(dt.timetuple()) + dt.microsecond/1e6
24.11.2021 · And then, instead of calling start_date.timestamp(), you just call to_seconds(start_date). Solution 2. The timestamp method was added in Python 3.3.So if you’re using Python 2.0, or even 2.7, you don’t have it. There are backports of current datetime to older Python versions on PyPI, but none of them seems to be official, or up-to-date; you might want …
22.07.2019 · python3 unix-timestamp.py. In case that is not possible e.g. due to incompatibilities, use this snippet instead, which is compatible with both Python 2 and Python 3: from datetime import datetime import time dt = datetime.now() timestamp = time.mktime(dt.timetuple()) + dt.microsecond/1e6
This line raises an AttributeError: "Timestamp object has no attribute 'dt'": df['count'] = df.apply(last_day, axis=1) this is what my dataframe looks like: start count 0 2016-02-15 NaN 1 2016-02-20 NaN 2 2016-04-23 NaN df.dtypes start datetime64[ns] count float64 dtype: object
Jan 01, 2020 · Series has an accessor ( dt) object for datetime like properties. However, the following is a TimeDelta with no dt accessor: type (df.loc [0, 'timestamp'] - df.loc [1, 'timestamp']) Just call the following (without the dt accessor) to solve the error:
31.10.2021 · Solution 1. The method to_datetime will return a TimeStamp instance. I’m not sure what you are hoping to accomplish by the lambda function, but it appears you are trying to convert some object to a TimeStamp. Try removing the apply section so it looks like this: Train ['timestamp'] = pd.to_datetime (Train ['date'])