Calculus I - Derivatives of Trig Functions
tutorial.math.lamar.edu › Classes › CalcIJun 11, 2018 · Or, in other words the two functions in the product, using this idea, are − w 2 − w 2 and tan ( w) tan ( w). Doing this gives, h ′ ( w) = − 12 w − 5 − 2 w tan ( w) − w 2 sec 2 ( w) h ′ ( w) = − 12 w − 5 − 2 w tan ( w) − w 2 sec 2 ( w) So, regardless of how you approach this problem you will get the same derivative.