Calculus I - Implicit Differentiation
tutorial.math.lamar.edu › Classes › CalcIMay 30, 2018 · There are actually two solution methods for this problem. Solution 1 : This is the simple way of doing the problem. Just solve for y y to get the function in the form that we’re used to dealing with and then differentiate. y = 1 x ⇒ y ′ = − 1 x 2 y = 1 x ⇒ y ′ = − 1 x 2. So, that’s easy enough to do.