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... I am using regex /Time|BYTES_RX_THROUGHPUT/ to select series that I am interested in. Is there a way to replace the maching 'BYTE…

Good day! I want to use variables in metrics, but I get an error when, I put “Include All option” checkbox, because there are characters “.

regex stage The regex stage is a parsing stage that parses a log line using a regular expression. Named capture groups in the regex support ...

Rename by regex. Use this transformation to rename parts of the query results using a regular expression and replacement pattern. You can ...

Using the Regex Query Option, you filter the list of options returned by the Variable query or modify the options returned. For more information, refer to the Mozilla guide on Regular expressions. Examples of filtering on the following list of options: backend_01 backend_02 backend_03 backend_04. Text.

regexReplaceAllLiteral function returns a copy of the input string and replaces matches of the Regexp with the replacement string replacement. The replacement string is substituted directly, without using Expand. ` { { regexReplaceAllLiteral " (ts=)" .timestamp "timestamp=" }}` You can combine multiple functions using pipe.

May 08, 2018 · Find and replace in templating variable values. Grafana. templating. nayeemnayyu May 8, 2018, 11:30am #1. I’m using grafana 4.6, when I create varible and fetch values from elasticsearch, it usually have semicolon at the end. So I want to remove or replace with something else. Is it possible to do it?

Your problem is not with the eks_cluster variable. This will just as much not work if the query is simply label_values(job=~".").

Using the Regex Query Option, you filter the list of options returned by the Variable query or modify the options returned. For more information, refer to the Mozilla guide on Regular expressions. Examples of filtering on the following list of options: backend_01 backend_02 backend_03 backend_04. Text.

Filter variables with regex Using the Regex Query option, you filter the list of options returned by the variable query or modify the options returned. …

The replace stage is a parsing stage that parses a log line using a regular expression and replaces the log line. Named capture groups in the regex support adding data into the extracted map. Schema replace: # The RE2 regular expression. Each named capture group will be added to extracted.

regex stage. The regex stage is a parsing stage that parses a log line using a regular expression. Named capture groups in the regex support adding data into the extracted map. Schema regex: # The RE2 regular expression. Each capture group must be named. expression: <string> # Name from extracted data to parse. If empty, uses the log message.

Aug 06, 2018 · Replacement is not part of regular expressions. That's something other libraries/programs/functions put on top. So the answer is no, there is no regex that can match and replace at the same time.

So I want to remove or replace with something else. Is it possible to do it? mefraimsson May 28, 2018, 1:34pm #2. Hi,. Use the regex field ...

I want to replace all the dev and prod to * in regex field on template variable page ... How can I achieve this in grafana?

Note: In Loki 2.1 replace (as opposed to Replace ) is available with a different ... regexReplaceAllLiteral function returns a copy of the input string and ...

Named capture groups in the regex support adding data into the extracted map. Schema. replace: # The RE2 regular expression. Each named capture ...

14.08.2020 · I want to replace all the dev and prod to * in regex field on template variable page. Final value something like. string1_*_01_08_2020 string1_*_01_08_2020 string2_*_02_08_2020 How can I achieve this in grafana? Thanks in advance.

Aug 14, 2020 · I want to replace all the dev and prod to * in regex field on template variable page. Final value something like. string1_*_01_08_2020 string1_*_01_08_2020 string2_*_02_08_2020 How can I achieve this in grafana? Thanks in advance.

05.08.2018 · I can't use methods like Replace so I need a Regex statement that will replace underscores and add a space instead. I thought that /([^_])/ would at least return the string without the underscore but it only returns certain strings with the first character.