Logarithmic Equations | College Algebra
courses.lumenlearning.com › logarithmic-equationsLogarithmic Equations. We have already seen that every logarithmic equation logb(x)= y l o g b ( x) = y is equal to the exponential equation by = x b y = x. We can use this fact, along with the rules of logarithms, to solve logarithmic equations where the argument is an algebraic expression. For example, consider the equation log2(2)+log2(3x−5)= 3 l o g 2 ( 2) + l o g 2 ( 3 x − 5) = 3.
Algebra - Solving Logarithm Equations
tutorial.math.lamar.edu › Classes › AlgJun 02, 2018 · log 2 ( ( − 4) 2 − 6 ( − 4)) = 3 + log 2 ( 1 − ( − 4)) log 2 ( 16 + 24) = 3 + log 2 ( 5) log 2 ( ( − 4) 2 − 6 ( − 4)) = 3 + log 2 ( 1 − ( − 4)) log 2 ( 16 + 24) = 3 + log 2 ( 5) So, upon substituting this solution in we see that all the numbers in the logarithms are positive and so this IS a solution.