Pandas explode error – column must be scalar. 134 views July 21, 2021 pythonexplode pandas python Attribution: ... ValueError: column must be a scalar.
Raises: ValueError : if columns of As per pandas documentation explode(): ... Scalars will be returned This routine will explode list-likes including lists, ...
Apr 20, 2020 · This answer is not useful. Show activity on this post. For those of you working with Pandas < 1.3, the following logic executes a multi-column explode and is reasonably efficient. Just need to replace the name of cols you want to explode. def explode (df): df ['tmp']=df.apply (lambda row: list (zip (row [col1],row [col2])), axis=1) df=df ...
Jul 04, 2017 · So I would be willing to reverse this if we then allow scalars in the constructor w/o an Index. I think that it would be better than nothing (also because, all else equal, for backward compatibility we prefer to allow than to disallow something new).
09.11.2018 · In my case with more than one column to explode, and with variables lengths for the arrays that needs to be unnested. I ended up applying the new pandas 0.25 explode function two times, then removing generated duplicates and it does the job ! df = df.explode('A') df = df.explode('B') df = df.drop_duplicates()
My goal is to list each element on it's own row. I can use the df.explode() . but it only accepts one column. However, I want the pair of the two columns to ...
01.09.2020 · pandas.apply expand column ValueError: If using all scalar values, you must pass an index. Ask Question Asked 1 year, 1 month ago. Active 1 year, 1 month ago. ... If using all scalar values, you must pass an index. I've tried to set the name of the output dataframe, ...
Exploded lists to rows of the subset columns; index will be duplicated for these rows. Raises. ValueError : If columns of the frame are not unique. If specified ...
Explode a DataFrame from list-like columns to long format. This routine will explode list-likes including lists, tuples, sets, Series, and np.ndarray. The result dtype of the subset rows will be object. Scalars will be returned unchanged, and empty list-likes will result in a np.nan for that row.