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22.08.2019 · 出现syntaxerror: 'return' outside function是由于python对格式要求严格的原因，多半问题是由于格式对齐导致的 根据报错提示到相应的.py文件的相应行修改缩进，只需要保持缩进为1或着2个tab即可，修改后保存.py文件后再次运行，直到不再报错即可 问题解决！

24.10.2012 · But it still shows 'return' outside function ... – lavitanien. Oct 25, 2012 at 12:12. 2. You still have inconsistend indention. Please use four spaces for each level of indention. Right now you still have four and eight spaces mixed. – user647772. Oct 25, 2012 at 12:14

CAUTION The octal numbers returned by this function are strings that cannot readily be used like common numbers in other formulas.

Syntaxerror: 'return' outside function ... This syntax error is nothing but a simple indentation error, generally, this error occurs when the indent or return ...

If you are using return, you will get the SyntaxError: return outside function in Python. This syntax error suggests that you are not using ...

23.12.2021 · To solve this error, we have to indent our return statement so that it is within the function. If we do not use the correct indentation, the Python interpreter will see the return statement outside the function. Let’s see the change in the revised code: # Function to convert temperature from Celsius to Fahrenheit def temp_converter (temp_c ...

This is my code: def fizz_count(x): count = 0 for item in x: if item == 'fizz': count = count + 1 return count My indenting is fine, I think, ...

15.08.2020 · To solve this syntaxerror: can’t assign to function call we have to assign a function call to a variable. We have to declare the variable first followed by an equals sign, followed by the value that should be assigned to that variable.

09.04.2021 · Return outside function Python. When you are working in a loop, you mistakenly use the return statement to break the loop instead of using the break or quit() function. If you are using return, you will get the SyntaxError: return outside function in Python.

The return statement only makes sense inside functions: def foo(): while True: return False.

If the return statement is not used properly, then Python will raise a SyntaxError alerting you to the issue. In some cases, the syntax error ...

warning: extra ';' outside of a function is a C++11 extension ... warning: parameter 'A' not in expected state when the function returns: expected 'B', ...

13.08.2020 · So, when you type in the return statement within the function the result is different than when the return statement is mentioned outside. It is best to check your indentation properly before executing a function to avoid any syntax errors.

07.10.2021 · The return keyword in Python is used to end the execution flow of the function and send the result value to the main program. The return statement must be defined inside the function when the function is supposed to end. But if we define a return statement outside the function block, we get the SyntaxError: 'return' outside function… Read More »

Dec 23, 2021 · In Python, the return keyword ends the execution flow of a function and sends the result value to the main program. You must define the return statement inside the function where the code block ends. If you define the return statement outside the function block, you will raise the error “SyntaxError: ‘return’ outside function”.

20.10.2021 · 在使用Python过程中出现问题：SyntaxError: ‘return’ outside function原因可能有：代码缩进有问题或者忘记定义方法，导致return语句没包含在方法中例如：你要定义如下函数：def func(num): for num in range(1,10): if num==5: print("I find '5'") returnfunc(5)错误一：如果你忘记写def func(num):如

Aug 15, 2020 · Python syntaxerror: 'return' outside function In python, this error can come when the indentation or return function does not match. Example: def add(x, y): sum = x

Introduction

Sep 25, 2020 · SyntaxError: ‘return’ outside function. Return statements can only be included in a function. This is because return statements send values from a function to a main program. Without a function from which to send values, a return statement would have no clear purpose. Return statements come at the end of a block of code in a function.

Oct 25, 2012 · File "temp.py", line 56 return result SyntaxError: 'return' outside function. Where was I wrong? class Complex (object): def __init__ (self, realPart, imagPart): self.realPart = realPart self.imagPart = imagPart def __str__ (self): if type (self.realPart) == int and type (self.imagPart) == int: if self.imagPart >=0: return '%d+%di'% (self.realPart, self.imagPart) elif self.imagPart <0: return '%d%di'% (self.realPart, self.imagPart) else: if self.imagPart >=0: return '%f+%fi'% (self.

“javascript access variable outside function” Code Answer's ; 1. var global = "Global Variable"; //Define global variable outside of function ; 2. ​ ; 3. function ...