The Fermat factorization method revisited
eprint.iacr.org › 2009 › 318The Fermat factorization method revisited Robert Erra∗ Christophe Grenier† 30th June 2009 Abstract We consider the well known Fermat factorization method, we call the Fermat factorization equation the equation solved by it: P(x,y) = (x + 2R)2 − y2 − 4N = 0; where N = pq > 0 is a RSA modulus with primes p and q supposed of equal length.
CTF: Eating a nice RSA buffet – Hackeriet
https://blog.hackeriet.no/eating-a-rsa-buffetWriteup. During the 2017 Boston Key Party we were presented with a very nice buffet of RSA keys to crack. There where 10 different keys and five of them decrypted five other cipher texts. Any three of those five could be combined with the help of secret sharing to get the flag. We used four different attacks on RSA in order to retrieve five of ...
The Fermat factorization method revisited
https://eprint.iacr.org/2009/318.pdfThe Fermat factorization method revisited Robert Erra∗ Christophe Grenier† 30th June 2009 Abstract We consider the well known Fermat factorization method, we call the Fermat factorization equation the equation solved by it: P(x,y) = (x + 2R)2 − y2 − 4N = 0; where N = pq > 0 is a RSA modulus with primes p and q supposed of equal length.
FactHacks: Fermat's factorization method
facthacks.cr.yp.to › fermatOne can save time in RSA decryption by choosing, e.g., p and q very close to 2^512. Fermat's factorization method shows that this is unsafe if "very close" means, e.g., between 2^512-2^256 and 2^512+2^256. Fermat's factorization method is also a first step towards understanding the quadratic sieve.
FactHacks: Fermat's factorization method
https://facthacks.cr.yp.to/fermat.htmlFermat's factorization method Fermat's factorization method factors N into p and q very quickly if p and q share half of their leading bits, i.e., if the gap between p and q is below the square root of p.It becomes much slower if p and q share significantly fewer bits.. One can save time in RSA decryption by choosing, e.g., p and q very close to 2^512. Fermat's factorization method shows …