17. Vandermonde determinants
www-users.cse.umn.edu › ~garrett › mVandermonde matrix all the top row entries have total degree 0, all the second row entries have total degree 1, and so on. Thus, in this permutation-wise sum for a Vandermonde determinant, each summand has total degree 0 + 1 + 2 + :::+ (n 1) = 1 2 n(n 1) so the total degree of the determinant is the total degree of the product X 1 i<j n 1 = X 1 ...