Wilson's Theorem - GeeksforGeeks
www.geeksforgeeks.org › wilsons-theoremDec 15, 2015 · Wilson’s theorem states that a natural number p > 1 is a prime number if and only if (p - 1) ! ≡ -1 mod p OR (p - 1) ! ≡ (p-1) mod p Examples: p = 5 (p-1)! = 24 24 % 5 = 4 p = 7 (p-1)! = 6! = 720 720 % 7 = 6 How does it work? 1) We can quickly check result for p = 2 or p = 3.
Wilson's Theorem - GeeksforGeeks
https://www.geeksforgeeks.org/wilsons-theorem15.12.2015 · Wilson’s Theorem. Difficulty Level : Easy. Last Updated : 19 Nov, 2016. Wilson’s theorem states that a natural number p > 1 is a prime number if and only if. (p - 1) ! ≡ -1 mod p OR (p - 1) ! ≡ (p-1) mod p. Examples: p = 5 (p-1)! = 24 24 % 5 = 4 p = 7 (p-1)! = 6! = 720 720 % 7 = 6. How does it work?
Wilson’sTheoremandFermat’sTheorem
sites.millersville.edu › wilson-fermatWilson’sTheoremandFermat’sTheorem Suppose pis prime. Wilson’s theorem says (p−1)! = −1 (mod p). Fermat’s theorem says if p6 |a, then ap−1 = 1 (mod p). They are often used to reduce factorials and powers mod a prime. I’ll prove Wilson’s theorem first, then use it to prove Fermat’s theorem. Lemma. Let pbe a prime and let 0 <x<p.
Wilson's theorem - Wikipedia
https://en.wikipedia.org/wiki/Wilson's_theoremIn number theory, Wilson's theorem states that a natural number n > 1 is a prime number if and only if the product of all the positive integers less than n is one less than a multiple of n. That is (using the notations of modular arithmetic), the factorial satisfies exactly when n is a prime number. In other words, any number n is a prime number if, and only if, (n − 1)! + 1 is divisible by n.
WILSON’S THEOREM: AN ALGEBRAIC APPROACH
alpha.math.uga.edu › ~pete › wilson_easyWe present several algebraic results inspired by Wilson’s Theorem { for all prime numbers p, we have (p 1)! 1 (mod p). The standard proof of Wilson’s Theorem proceeds by evaluating the product of all elements in the unit group U(p) { that is, the group of nonzero residues modulo punder multiplication { by a pairing o argument.