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02.04.2011 · Thanks for that SredniVashtar with regards to position I need to make some kind of rule for n, I tried liss = 7 - li to get {-11, -15, 3, -3} But I come up with difficulties because if I had 11 -li which gives me {-7, -11, 7, 1} I need to find the position of the smallest positive number

Details and Options. Position [ expr, pattern] tests all the subparts of expr in turn to try and find ones that match pattern. Position returns a list of positions in a form suitable for use in Extract, ReplacePart, and MapAt. The form is different from the one used in Part.

Position[expr, pattern] gives a list of the positions at which objects matching pattern appear in expr. Position[expr, pattern, levelspec] finds only objects that appear on levels specified by levelspec. Position[expr, pattern, levelspec, n] gives the positions of the first n objects found. Position[pattern] represents an operator form of Position that can be applied to an expression.

Lists, 15, 34,444 array depth of, ArrayDepth, 444 as collections of elements, ... With, 522 extrema, FindMinimum, 759 regression, localRegress, 1038 rules, ...

An old trick used to find the minimum is to find the max of -1 times the data. data = {1, 3, 1, 3};FindPeaks[data]. which gives {{2, 3}, {4, 3}}.

we can use max [examplelist] or min [examplelist] to find the maxima and minima of examplelist, however, is there a similar standalone function that returns …

You can try with lists functions Max or Min or Position... lna = RandomInteger[999, 600] ...

FindMinimum returns a list of the form { f min, { x -> x min } }, where f min is the minimum value of f found, and x min is the value of x for which it is found. If the starting point for a variable is given as a list, the values of the variable are taken to be lists with the same dimensions.

I am generating a list of numbers between 0 and 1, using a cicle and a function I wrote . Because I am trying to solve an optimization process I need to extract the smallest of this number (and this is easy using the function Min) but I don't know how to extract the position of the minimum, in what position of the array the minimum value is stored.

How can I find the indices i and j of all nonzero elements of a matrix. ... The difficulty is that Mathematica, in contrast to some programming

Open Mathematica Notebook. Let's see where the bottleneck is. Finding the minimal really takes no time but the Position function is surprisingly slow. (min ...

We can use Max[exampleList] or Min[exampleList] to find the maxima and minima of exampleList, however, is there a similar standalone function that returns something like {position in array, maximum value in the array} or {position in array, minimum value in the array}, i.e. both the position and value of the maximum or minimum element in ...

Mar 18, 2012 · 2 9. Another approach is of course sorting the list by user-defined rules and then picking the first/last element. For example, the following sorts the list according to ascending y values, and then extracts the min/max from that. sorted = Sort [rand, #1 [ [2]] < #2 [ [2]] &] sorted [ [1, 2]] (* Minimal y *) sorted [ [-1, 2]] (* Maximal y *) 2 ...

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Position[list,_?(#==Max[list]&)]. or shorter (per your comment...) Position[list,Max[list]]. will do the trick, obviously change Max to Min for minimum.

Apr 01, 2011 · Thanks for that SredniVashtar with regards to position I need to make some kind of rule for n, I tried liss = 7 - li to get {-11, -15, 3, -3} But I come up with difficulties because if I had 11 -li which gives me {-7, -11, 7, 1} I need to find the position of the smallest positive number

I am generating a list of numbers between 0 and 1, using a cicle and a function I wrote . Because I am trying to solve an optimization process I need to extract the smallest of this number (and this is easy using the function Min) but I don't know how to extract the position of the minimum, in what position of the array the minimum value is stored.

02.05.2015 · An old trick used to find the minimum is to find the max of -1 times the data. data = {1, 3, 1, 3};FindPeaks [data] which gives { {2, 3}, {4, 3}} To get the minimum use negate the data FindPeaks [-data] which gives { {1, -1}, {3, -1}} The x position is correct, but the y is negated. So multiply -1 times those y values.

May 03, 2015 · An old trick used to find the minimum is to find the max of -1 times the data. The x position is correct, but the y is negated. So multiply -1 times those y values. Note: That # and & is a Mathematica shorthand for defining a tiny little function with argument named #.