srch

Aug 27, 2011 · binSearch[lst_,threshold_]:= binSearchRec[lst,threshold,1,Length@lst] (* return position of leftmost element greater than threshold breaks if the first element is greater than threshold lst must be sorted *) binSearchRec[lst_,threshold_,min_,max_] := Module[{i=Floor[(min+max)/2],element}, element=lst[[i]]; Which[ min==max,max, element <= threshold,binSearchRec[lst,threshold,i+1,max], (element > threshold) && ( lst[[i-1]] <= threshold ), i, True, binSearchRec[lst,threshold,min,i-1] ] ]

Dec 13, 2021 · More than 600 new functions in Version 13 plus loads of updates covering: symbolic integration, mathematical functions, PDE modeling, video creation, image stitching, tree constructs, graph coloring, subgraph isomorphism, spatial fields, leap seconds, maps, geometric regions, chemical formulas & reactions, bio sequences, flight data, multiaxis plots, dates as coordinates, infinite plot scales ...

Say I have a list x= {2,4,6,8,10} and I want to find out the positions of the elements that are greater than 7. Select [x, #>7&] gives the elements themselves, and Position [x,8] gives the position of the elements satisfying one of the possible criteria, but what I am looking for would be a mix of the two returning {4,5}.

Select[list, crit] picks out all elements ei of list for which crit[ei] is True. Select[list, crit, n] picks out the first n elements for which crit[ei] is True. Select[crit] represents an operator form of Select that can be applied to an expression.

Say I have a list x={2,4,6,8,10} and I want to find out the positions of the elements that are greater than 7. Select[x, #>7&] gives the elements themselves, ...

This is definitely untolerable since this functionality will be called over and over in my use case. l = RandomReal[{0, 10}, 10^8]; {#, Position[l, #][[1, ...

Find the position of a select element. Replace parts of a list. ... Take 50 random words, dropping ones longer than 5 characters, and reversing others: ...

I now understand more about how Mathematica optimizes computation. Thank you again ... As you can see from my example code above, I do not really like that, ...

binSearch[lst_,threshold_]:= binSearchRec[lst,threshold,1,Length@lst] (* return position of leftmost element greater than threshold breaks ...

Select elements in the list that are greater than 3: ... Select letters that appear after position 10 in the alphabet: ...

space) by the greater than key. The first keystroke after inputting these ( -> ) will generate the arrow you see. • Notice that the styles Red, Dashed, Orange, Thick all start with capital letters, and the list of commands is contained in braces. Suppose in the graph above that we want to change the color of the x4 curve to purple (but keep

FindPeaks [ list] automatically chooses scale, sharpness and threshold parameters. To avoid the detection of noise-related peaks, the input is regularized by performing a Gaussian filtering using the standard deviation σ. The value of σ defaults to , with n being the number of data points in list.

26.08.2011 · I changed the Ceiling function to a Floor function to correctly handle recurring elements in the list. It is needed because if the threshold is between elements n and n+1 then BinarySearch returns n+1/2.The code I wrote works perfectly, and does indeed return the first (leftmost) element which is greater than the threshold (the request was not for a matching …

You can do this by using Select, and giving your test as a pure function. Select elements in the list that are greater than 3: In [8]:=. Out [8]=. Select elements that are between 2 and 5: In [9]:=. Out [9]=. Beyond size comparisons like <, > and ==, the Wolfram Language includes many other kinds of tests.

This functionality is provided by Mathematica's NDSolve function , which ... What happens if the hand controller keeps in the same position over a long ...

Position returns a list of positions in a form suitable for use in Extract, ReplacePart, and MapAt. The form is different from the one used in Part. Position looks only for matches to values in Association objects that appear in expr. It returns any part specifications within Association objects in the form Key [ k].

21.01.2017 · Thus a more specific question could be: How to know on each range, which function is greater than the other? calculus integration functions graphing-functions area Share

Say I have a list x= {2,4,6,8,10} and I want to find out the positions of the elements that are greater than 7. Select [x, #>7&] gives the elements themselves, and Position [x,8] gives the position of the elements satisfying one of the possible criteria, but what I am looking for would be a mix of the two returning {4,5}.

I was wondering how I could obtain the first element of a (already ordered) list that is greater than a given threshold. I don't know really well the list manipulation function in Mathematica, maybe someone can give me a trick to do that efficiently.

Wolfram|One · Mathematica · Wolfram|Alpha Notebook Edition · Finance Platform · System Modeler ... Fewer than the requested elements may be returned:.

Position[expr, pattern] gives a list of the positions at which objects matching pattern appear in expr. Position[expr, pattern, levelspec] finds only ...

Position[expr, pattern] gives a list of the positions at which objects matching pattern appear in expr. Position[expr, pattern, levelspec] finds only objects that appear on levels specified by levelspec. Position[expr, pattern, levelspec, n] gives the positions of the first n objects found. Position[pattern] represents an operator form of Position that can be applied to an expression.