Math 241: Solving the heat equation
www2.math.upenn.edu › solving_the_heat_eqnA more fruitful strategy is to look for separated solutions of the heat equation, in other words, solutions of the form u(x;t) = X(x)T(t). If we substitute X (x)T t) for u in the heat equation u t = ku xx we get: X dT dt = k d2X dx2 T: Divide both sides by kXT and get 1 kT dT dt = 1 X d2X dx2: D. DeTurck Math 241 002 2012C: Solving the heat equation 9/21
2 Heat Equation - Stanford University
web.stanford.edu › class › math220binvolves looking for a solution of a particular form. In particular, we look for a solution of the form u(x;t) = X(x)T(t) for functions X, T to be determined. Suppose we can find a solution of (2.2) of this form. Plugging a function u = XT into the heat equation, we arrive at the equation XT0 ¡kX00T = 0: Dividing this equation by kXT, we have T0 kT = X00 X = ¡‚:
Solving the Heat Equation (Sect. 10.5). Review: The ...
users.math.msu.edu › users › gnagyCompute the solution to the IBVP for the Heat Equation, u(t,x) = X∞ n=1 c n u n(t,x). u(t,x) = X∞ n=1 c n e −k(nπ L)2t sin nπx L . By construction, this solution satisfies the boundary conditions, u(t,0) = 0, u(t,L) = 0. Given a function f with f (0) = f (L) = 0, the solution u above satisfies the initial condition f (x) = u(0,x) iff holds f (x) = X∞ n=1 c n sin
Heat equation - Wikipedia
https://en.wikipedia.org/wiki/Heat_equationIn mathematics, if given an open subset U of R and a subinterval I of R, one says that a function u : U × I → R is a solution of the heat equation if where (x1, …, xn, t) denotes a general point of the domain. It is typical to refer to t as "time" and x1, …, xn as "spatial variables," even in abstract contexts where these phrases fail to have their intuitive meaning. The collection of spatial variables is often referred to simply as x. For any give…