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Ordering[list] gives the positions in list at which each successive element of Sort[list] appears. Ordering[list, n] gives the positions in list at which the first n elements of Sort[list] appear. Ordering[list, -n] gives the positions of the last n elements of Sort[list]. Ordering[list, n, p] gives positions in list of elements of Sort[list, p].

04.04.2017 · Show activity on this post. I would like to place the legend inside the plot frame. I have been doing a search in the documentation but only found option. ChartLegends -> Placed [ {"label", {Center}] Other options, such as Up, Bottom, Right, place the label outside.

Position[expr, pattern] gives a list of the positions at which objects matching pattern appear in expr. Position[expr, pattern, levelspec] finds only ...

Using DSolve we do only tell Mathematica the definition of velociy (the derived function of the position) and the definition of acceleration (the double ...

Position returns a list of positions in a form suitable for use in Extract, ReplacePart, and MapAt. The form is different from the one used in Part. Position looks only for matches to values in Association objects that appear in expr. It returns any part specifications within Association objects in the form Key [ k].

StringPosition returns sequence specifications in the form used by StringTake, StringDrop, and StringReplacePart. ». StringPosition [ " string ", RegularExpression [ " regex "]] gives positions of substrings matching the specified regular expression. StringPosition [ patt] [ expr] is equivalent to StringPosition [ expr, patt].

(* This code extends Mathematica's Position function to work on SparseArrays. *). (* Note that Position and Cases have the same optional arguments, ...

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Position[{2, 4, 6, 8, 10}, _?(# > 7 &)] does the job. Apply Flatten[] if need be. As noted by Dan in a comment alluding to Brett's answer, using the ...

Say I have a list x={2,4,6,8,10} and I want to find out the positions of the elements that are greater than 7. Select[x, #>7&] gives the elements themselves, and Position[x,8] gives the position of the elements satisfying one of the possible criteria, but what I am looking for would be a mix of the two returning {4,5}. Any suggestions?

Reason: The reason is that Position takes a pattern not a function. (i.e. Position[-list-,-pattern-]). Solution: Position[myList, x_ /; x ...

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Copy to clipboard. deletes the element at position n in expr. If n is negative, the position is counted from the end. Copy to clipboard. Delete [ expr, { i, j, …. }] deletes the part at position { i, j, …. }. Copy to clipboard.

Details. To use LegendPosition, you first need to load the Plot Legends Package using Needs [ "PlotLegends`"]. Places the lower ‐ left corner of a legend box in a position specified by a coordinate system scaled so the center of the graphic is at , and the longest side of the graphic runs from -1 to 1.

Oct 29, 2013 · The task I have is pretty simple but I can not solve it in mathematica. Given a list. myList = {1, 3, 4} I would like to get the position of entries smaller than a number - say 2 in the example above. Attempts such as . Position[myList, #[[1]] < 2 &] Position[myList, # < 2 &] which would be similar to the function SELECT don't work.

One reason is that Position tries to find all occurences but I only need one. We can instead use FirstPosition to avoid search the entire list. Now the time is ...

Position is certainly the best for the job, but for the sake of completeness, you can do this in a way similar to Select: DeleteCases[MapIndexed[If[#1 > 7, #2] &, {2, 4, 6, 8, 10}], Null] While inefficient when you select only on content, this form allows to mix criteria on the content and position.

Position[expr, pattern] gives a list of the positions at which objects matching pattern appear in expr. Position[expr, pattern, levelspec] finds only objects that appear on levels specified by levelspec. Position[expr, pattern, levelspec, n] gives the positions of the first n objects found. Position[pattern] represents an operator form of Position that can be applied to an expression.

Career Opportunities. Mathematica's reputation for quality and objectivity is based in no small part on our high-caliber staff. Visit Mathematica Careers to browse current openings in public policy, health, data analytics, education research, and more. We at Mathematica take pride in our employees and in their commitment to excellence.